Answer:

The work done on a 12.3-kg object is 75 Joules. Therefore, the correct answer is (e).

Problem

We are tasked to find the work done on a 12.3-kg object where the net force is given by the function [tex]F(x)=(20-x)[/tex], where [tex]F(x)[/tex] is in Newtons and [tex]x[/tex] is in meters. The object moves from [tex]x=0[/tex] to [tex]x=15[/tex] meters.

Solution

Given

• [tex]F(x)=(20-x)[/tex] (net force)
• [tex]\Delta x=x_2-x_1\Rightarrow15-0=15\ m[/tex] (displacement)

Required

• amount of work done

Formula

• [tex]W=F\times s[/tex], where [tex]F[/tex] is the net force and [tex]x[/tex] is the displacement

Solving

Substitute the given into the formula of work.

[tex]\Rightarrow W=(20-x)\ \cdot\ x[/tex]

[tex]\Rightarrow W=(20-15)\ N\ \cdot\ 15\ m[/tex]

[tex]\Rightarrow W=5\ N\ \cdot\ 15\ m[/tex]

[tex]\Rightarrow W=75\ Nm[/tex]

Therefore, the amount of work done is 75 Newton-meter or 75 Joules.

Additional Discussion

Work, in physics, is defined as the "dot product of force and displacement." If a force is applied to an object making it move to a significant distance, then, we can say that there is work is done.

Suppose you are pushing a heavy cart from position A to position B at a distance of 3 meters. Here, work is done. However, if the cart remained on the spot despite how hard you push it, then, there is NO work done. Since work depends on displacement, it means that the moving object must not go back to its original position. It should move farther away from position A.

The unit for work is Joule (or Nm).

Learn More

Check out these links for more info about work:

https://brainly.in/question/26312552

https://brainly.ph/question/340936

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