Answer:
dual nature of radiation and matter.
givern. V=6×10+14Hz
power emitted by light p=2×10−3w
energy of one photon is given by
energy =hv→i
Number of photons emitted per second =enwrgy of one photonpower
=6.63×10−34×6×10142×10−3
⇒ 5.03×1015 → ii
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Answers & Comments
Answer:
dual nature of radiation and matter.
givern. V=6×10+14Hz
power emitted by light p=2×10−3w
energy of one photon is given by
energy =hv→i
Number of photons emitted per second =enwrgy of one photonpower
=6.63×10−34×6×10142×10−3
⇒ 5.03×1015 → ii