Answer:
The molar mass of iron (III) sulfate, Fe₂(SO₄)₃, can be calculated by adding the atomic masses of its constituent elements.
- Iron (Fe) has an atomic mass of approximately 55.85 g/mol.
- Sulfur (S) has an atomic mass of approximately 32.07 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
Now, let's calculate the molar mass of Fe₂(SO₄)₃:
Molar mass = 2(Fe) + 3(S) + 12(O) = 2(55.85 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) = 111.70 g/mol + 96.21 g/mol + 192.00 g/mol = 399.91 g/mol
So, the molar mass of iron (III) sulfate, Fe₂(SO₄)₃, is approximately 399.91 grams per mole.
Explanation:
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Answer:
The molar mass of iron (III) sulfate, Fe₂(SO₄)₃, can be calculated by adding the atomic masses of its constituent elements.
- Iron (Fe) has an atomic mass of approximately 55.85 g/mol.
- Sulfur (S) has an atomic mass of approximately 32.07 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
Now, let's calculate the molar mass of Fe₂(SO₄)₃:
Molar mass = 2(Fe) + 3(S) + 12(O) = 2(55.85 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) = 111.70 g/mol + 96.21 g/mol + 192.00 g/mol = 399.91 g/mol
So, the molar mass of iron (III) sulfate, Fe₂(SO₄)₃, is approximately 399.91 grams per mole.
Explanation:
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