Answer:

sum of the four angles of a quadrilateral is 360°

let each of the equal angles is x°

so,

(52+110+x+x)°=360°

=> (162+2x)°=360°

=> 2x°=(360-162)°=198°

=> x=198/2°=99°

so,each of equal angles are 99°

let the quadrilateral be abcd

Angle a=angle b

angle c=52 angle d=110

Angle a+ angle b+angle c+ angle d=360

x+x+52+110=360

2x+162=360

2x=360-162

x=198/2

x=99.