Answer:
Step-by-step explanation:
Let ABCD be the rectangular of length l and width w Now, we construct a triangle of maximum area inside it in all possible ways-
The area of triangle=
2
1
×Base×Height
Maximum base length = l
Maximum height = w
Therefore, are(maximum) of triangle =
=
×l×w=
l×w
sq units
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Answers & Comments
Answer:
Step-by-step explanation:
Let ABCD be the rectangular of length l and width w Now, we construct a triangle of maximum area inside it in all possible ways-
The area of triangle=
2
1
×Base×Height
Maximum base length = l
Maximum height = w
Therefore, are(maximum) of triangle =
=
2
1
×l×w=
2
l×w
sq units
[tex]Area \: of \: Triangle \\ = \frac{1}{2} \times b \times h[/tex]
[tex] = \frac{1}{2} \times a \times b \\ = \frac{a + b}{2} [/tex]