The length of a wire is increased to twice while keeping its volume constant. The
resistivity
of wire become
By increasing the
volume of a wire fixed, its length is increased to double The
resistivity of the wire becomes
resistivity
of wire become
By increasing the
volume of a wire fixed, its length is increased to double The
resistivity of the wire becomes
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Answer:
4 times
Explanation:
if length is twiced having constant volume then cross-section area become half .then find new resistance by formula rho.l/A . then we will get 4 R (R=initial resistance)
Given : The length of a wire is increased to twice while keeping its volume constant.
To Find: The resistivity of wire become
Solution:
R = ρ L/A
R = Resistance of wire
ρ = Resistivity of wire
L = Length of wire
A = Cross sectional Area of wire
Resistivity of wire is a material property and does not depend upon dimensions of conductor
Resistivity Vary with ambient temperature but thats not mentioned here hence to be ignored
Hence Increasing decreasing length will not make any change in resistivity.
Resistivity will remains same .
If Question is about Resistance
then R = ρ L/A
New L' = 2L
As volume is constant and Volume = Area * Length
=> AL = A'L'
=> AL = A' 2L
=> A' = A/2
R' = ρ L'/A'
=> R' = ρ2L/(A/2)
=> R' = 4ρ L/A
=> R' = 4R
Hence Resistance becomes 4 times
but Resistivity remains same.
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