Sure, let's solve this step by step:
1. Let's denote the width of the field as `w` (in meters). According to the problem, the length of the field is `w + 25` meters.
2. The perimeter of a rectangle is given by the formula `2*(length + width)`. In this case, it's `2*(w + (w + 25))`.
3. We know that the perimeter is 150 meters. So we can set up the equation: `2*(w + (w + 25)) = 150`.
4. Simplifying this equation gives us `2w + 50 = 75`, or `2w = 75 - 50`, which simplifies to `2w = 25`.
5. Solving for `w`, we get `w = 25/2 = 12.5` meters.
6. Substituting `w = 12.5` into the length expression `w + 25` gives us the length as `12.5 + 25 = 37.5` meters.
So, the width of the field is 12.5 meters and the length is 37.5 meters.
I hope this helps!
If you have any other questions, feel free to ask.
150 = 2(a + 2a)
1502a + 4a
150 = 6a
150/6 = a
25 = a
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Answers & Comments
Sure, let's solve this step by step:
1. Let's denote the width of the field as `w` (in meters). According to the problem, the length of the field is `w + 25` meters.
2. The perimeter of a rectangle is given by the formula `2*(length + width)`. In this case, it's `2*(w + (w + 25))`.
3. We know that the perimeter is 150 meters. So we can set up the equation: `2*(w + (w + 25)) = 150`.
4. Simplifying this equation gives us `2w + 50 = 75`, or `2w = 75 - 50`, which simplifies to `2w = 25`.
5. Solving for `w`, we get `w = 25/2 = 12.5` meters.
6. Substituting `w = 12.5` into the length expression `w + 25` gives us the length as `12.5 + 25 = 37.5` meters.
So, the width of the field is 12.5 meters and the length is 37.5 meters.
I hope this helps!
If you have any other questions, feel free to ask.
Verified answer
what is your name?
Answer:
150 = 2(a + 2a)
1502a + 4a
150 = 6a
150/6 = a
25 = a