Answer:
√170 or approximately 13.038 units
Step-by-step explanation:
Point J(-4,8) and Point K(7,15)
Let x1 = -4 , x2 = 7 , y1 = 8 , y2 = 15
Recall the distance formula
D = √(x2-x1)²+(y2-y1)²
D = √(7-(-4))² + (15-8)²
D = √(7+4)² + (7)²
D = √(11)²+ (7)²
D = √121+49
D = √170
D ≈ 13.038
Length = √170 or approximately 13.038 units
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Answers & Comments
Answer:
√170 or approximately 13.038 units
Step-by-step explanation:
Point J(-4,8) and Point K(7,15)
Let x1 = -4 , x2 = 7 , y1 = 8 , y2 = 15
Recall the distance formula
D = √(x2-x1)²+(y2-y1)²
D = √(7-(-4))² + (15-8)²
D = √(7+4)² + (7)²
D = √(11)²+ (7)²
D = √121+49
D = √170
D ≈ 13.038
Length = √170 or approximately 13.038 units