Answer:
a. let width be x and length be x+120
b. A = x ( x+120)
c. x ( x+120) = 6400
x² + 120x = 6400
x²+ 120x - 6400 = 0
by factoring:
( x + 160) (x- 40 ) = 0
use x-40=0 : x+160 = 0 results into a negative answer
so: x= 40
d. since width is represented by the variable x, width is 40 m
length is 120 m more than its width so 40 + 120 = 160 m
e. yes the L and W will also double
since:
A= l x w
2(A) = 2 ( l x w)
2A = 2l x 2w
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Answers & Comments
Answer:
a. let width be x and length be x+120
b. A = x ( x+120)
c. x ( x+120) = 6400
x² + 120x = 6400
x²+ 120x - 6400 = 0
by factoring:
( x + 160) (x- 40 ) = 0
use x-40=0 : x+160 = 0 results into a negative answer
so: x= 40
d. since width is represented by the variable x, width is 40 m
length is 120 m more than its width so 40 + 120 = 160 m
e. yes the L and W will also double
since:
A= l x w
2(A) = 2 ( l x w)
2A = 2l x 2w