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AnswEr:-

Given:-

• Length and breadth of rectangular field is in ratio 3:2.

• The cost of fencimg the field at ₹50 per meter is ₹25000.

To Find:-

• The Area of the rectangular field.

Formulas Used:-

• Perimeter of rectangle,

= 2 (length + breadth).

• Area of rectangle,

= Length × Breadth.

So here,

It is given that length and breadth are in ratio 3:2.

So let the length and breadth of the rectangle be 3x meters and 2x meters respectively.

Also the cost of fencing at ₹50 per meter is ₹25000.

This means that 50 times the perimeter of rectangle is 25000.

So lets make an equation by using above data:-

=》 50 × [2 × (3x+2x)] = 25000.

=》 50 × [2 × 5x] = 25000.

=》 50 × 10x = 25000.

=》 500x = 25000.

=》 x = 25000/500.

=》 x = 50.

Therefore,

=》 Length of field = 3x meters.

= 3 × 50 meters.

= 150 meters.

And,

=》 Breadth of the field = 2x meters.

= 2 × 50 meters.

= 100 meters.

So the area of the field,

= Length × Breadth.

= 150 meters × 100 meters.

= 15000 meters².

Therefore the area of the given rectangular field is 15,000 meters² .

Answer:

Step-by-step explanation:

let the lenght and breadth be 3x and 2x respectively

perimeter of rectangular field = 2(l+b)

                                                =2(3x +2x)

                                                 =2 x 5x

                                                 = 10x

now; 1m cost = Rs 50

       cost of 10x = rs 50 x 10x = Rs 500x

Now; 500x = 25000

          x       =    25000 ÷ 500

          x        =        50 m

so, length of rectangular field = 3x = 3 x 50 = 150 m

     Breadth of rectangular field = 2x = 2 x 50 = 100 m

Now : Area of field = L x B

                                =  150 x 100 m sq.

                                = 15,000 m sq. Ans

hence, area of field is 15,000.

                          I hope it will help you.