Step-by-step explanation:
Perimeter = 118\frac{1}{3}11831 yard
Length = 65 yard
Breadth = 5\frac{1}{3} = \frac{160}{3}531=3160
Perimeter = 2( L + B)
⇒ (\frac{65}{1} + \frac{160}{3} )(165+3160)
⇒ \frac{65*3\ +\ 160}{3}365∗3 + 160
⇒ \frac{355}{3}3355
⇒ 118\frac{1}{3}11831
[tex]\huge{\fcolorbox{maroon}{s} {\large{\fcolorbox{white}{mistyrose}{{\fcolorbox{gold} {White}{Solution}}}}}}[/tex]
Length of soccer field = 65 yards
Breadth of soccer field = 53 wholes 1 by 3 yards
[tex] = > \: 53 \frac{1}{3} = \frac{160}{3} \\ [/tex]
So, soccer field is a rectangle.
We know that
Perimeter of rectangle = 2 × ( l + b )
According to the question,
[tex] = > \: 2 \times (65 + \frac{160}{3} ) \\ [/tex]
[tex] = > \: 2 \times \frac{355}{3} \\ [/tex]
[tex] = > \: \frac{710}{3} \\ [/tex]
[tex] = > \: 236 \frac{2}{3} \: yards \\ [/tex]
Therefore, the above fraction is the perimeter of the soccer field.
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Answers & Comments
Step-by-step explanation:
Perimeter = 118\frac{1}{3}11831 yard
Step-by-step explanation:
Length = 65 yard
Breadth = 5\frac{1}{3} = \frac{160}{3}531=3160
Perimeter = 2( L + B)
⇒ (\frac{65}{1} + \frac{160}{3} )(165+3160)
⇒ \frac{65*3\ +\ 160}{3}365∗3 + 160
⇒ \frac{355}{3}3355
⇒ 118\frac{1}{3}11831
Verified answer
[tex]\huge{\fcolorbox{maroon}{s} {\large{\fcolorbox{white}{mistyrose}{{\fcolorbox{gold} {White}{Solution}}}}}}[/tex]
Given :
Length of soccer field = 65 yards
Breadth of soccer field = 53 wholes 1 by 3 yards
[tex] = > \: 53 \frac{1}{3} = \frac{160}{3} \\ [/tex]
Solution :
So, soccer field is a rectangle.
We know that
Perimeter of rectangle = 2 × ( l + b )
According to the question,
[tex] = > \: 2 \times (65 + \frac{160}{3} ) \\ [/tex]
[tex] = > \: 2 \times \frac{355}{3} \\ [/tex]
[tex] = > \: \frac{710}{3} \\ [/tex]
[tex] = > \: 236 \frac{2}{3} \: yards \\ [/tex]
Therefore, the above fraction is the perimeter of the soccer field.