To solve this problem, we can use the combined gas law:

(P1 V1) / T1 = (P2 V2) / T2

where P is the pressure, V is the volume, and T is the temperature of the gas.

We are given that the initial temperature of the neon gas is 289 K and the final temperature is 323 K. We are also given that the final volume is 2.3 L. Let's assume that the pressure remains constant.

Substituting the given values into the combined gas law, we get:

(P1 V1) / 289 = (P1 * 2.3) / 323

Simplifying this equation, we get:

V1 / 289 = 2.3 / 323

V1 = (2.3 x 289) / 323

V1 = 2.06 L

Therefore, the initial volume of the neon gas is approximately 2.06 L.

So the answer is closest to option C: 2.0 L.

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