Answer:
By definition, HCF divides the two numbers perfectly.
By definition, two numbers perfectly divide the LCM.
=> LCM should be a multiple of HCF. ( HCF should be a factor of LCM ).
=> The combination HCF = 30 and LCM = 45 doesn't exist.
The relation HCF x LCM = Product of two numbers should not be blindly appilid
solution
HCF (a, b) = 30
LCM (a, b) = 45
Since, for two numbers
HCF (a, b) × LCM (a, b) = a × b
So,
a × b = 30 × 45 = 1350
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Answers & Comments
Answer:
By definition, HCF divides the two numbers perfectly.
By definition, two numbers perfectly divide the LCM.
=> LCM should be a multiple of HCF. ( HCF should be a factor of LCM ).
=> The combination HCF = 30 and LCM = 45 doesn't exist.
The relation HCF x LCM = Product of two numbers should not be blindly appilid
solution
HCF (a, b) = 30
LCM (a, b) = 45
Since, for two numbers
HCF (a, b) × LCM (a, b) = a × b
So,
a × b = 30 × 45 = 1350