Answer:
Solution : When the distance is reduced to `1/4th` <br> `F. =G (Mm)/((1/4 d)^(2))=16G (Mm)/(d^(2))=16F` <br> The force between the two objects becomes 16 times.
Explanation:
According to the Universal law of gravitation,
F
=
G
m
1
2
r
Inititally,
Finally,
′
(
4
)
×
16
⇒
Thus the gravitational force between two objects increases by 16 times.
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Answers & Comments
Answer:
Solution : When the distance is reduced to `1/4th` <br> `F. =G (Mm)/((1/4 d)^(2))=16G (Mm)/(d^(2))=16F` <br> The force between the two objects becomes 16 times.
Verified answer
Explanation:
According to the Universal law of gravitation,
F
=
G
m
1
m
2
r
2
Inititally,
F
=
G
m
1
m
2
r
2
Finally,
F
′
=
G
m
1
m
2
(
r
4
)
2
=
G
m
1
m
2
r
2
×
16
⇒
F
′
=
16
F
Thus the gravitational force between two objects increases by 16 times.