Answer:

(1) (x, y) = (any value of x, (3/2)x + 1/2)

(2) (x, y) = (any value of x, (1/4)x + 13/4)

(3) (x, y) = (any value of x, x)

(4) (x, y) = (any value of x, (2/3)x - 1)

(5) (x, y) = (any value of x, 4x + 3)

Step-by-step explanation:

To find the ordered pair for each formula, we need to solve for x and y.

For 3x - 2y = -1, let's solve for y:

3x - 2y = -1

-2y = -3x - 1

y = (3/2)x + 1/2

For -x + 4y = 13, let's solve for y:

-x + 4y = 13

4y = x + 13

y = (1/4)x + 13/4

For -5x + 5y = 0, let's solve for y:

-5x + 5y = 0

5y = 5x

y = x

For 2x - 3y = 3, let's solve for y:

2x - 3y = 3

-3y = -2x + 3

y = (2/3)x - 1

For y = 4x + 3, we already have y expressed in terms of x.

Now we have the following ordered pairs:

(1) (x, y) = (any value of x, (3/2)x + 1/2)

(2) (x, y) = (any value of x, (1/4)x + 13/4)

(3) (x, y) = (any value of x, x)

(4) (x, y) = (any value of x, (2/3)x - 1)

(5) (x, y) = (any value of x, 4x + 3)

We cannot determine a specific ordered pair without a value for x, but we can use any value of x to find a corresponding value of y.