Answer:
(i)63° (ii)27°
Step-by-step explanation:
In ΔPQS, ∡QPS = 90°[Angle in a semi-circle is 90°]
By angle sum property,
∡QPS + ∡PSQ + ∡PQS = 180°
90° + 27° + ∡PQS = 180°
⇒ ∡PQS = 63°
In ΔRQS, ∡QRS = 90°[Angle in a semi-circle is 90°]
∡QRS + ∡RSQ + ∡RQS = 180°
90° + ∡RSQ + 63° = 180°
⇒ ∡PSR = 27°
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Answers & Comments
Answer:
(i)63° (ii)27°
Step-by-step explanation:
In ΔPQS, ∡QPS = 90°[Angle in a semi-circle is 90°]
By angle sum property,
∡QPS + ∡PSQ + ∡PQS = 180°
90° + 27° + ∡PQS = 180°
⇒ ∡PQS = 63°
In ΔRQS, ∡QRS = 90°[Angle in a semi-circle is 90°]
By angle sum property,
∡QRS + ∡RSQ + ∡RQS = 180°
90° + ∡RSQ + 63° = 180°
⇒ ∡PSR = 27°