y=x+1
z=2(×+1)
y+z
(x+1) + 2(x+1)
(x+1) + 2x+2
x+2x+1+2
3x + 3
b. 3x + 3
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y=x+1
z=2(×+1)
y+z
(x+1) + 2(x+1)
(x+1) + 2x+2
x+2x+1+2
3x + 3
b. 3x + 3