[tex]\large{Question:-}[/tex]
The figure shows Me Dhingra's verandah. How many square tiles is side 20cm would he need to tile the floor of the verandah?
Solutions:-
Let us divide the verandah into the rectangle 1 and 2.
Area of rectangle 1 = [tex]\sf{3m×2m=6 \:sq \:m.}[/tex]
Area of rectangle 2 = [tex]\sf{7m×2m=14 \:sq \:m.}[/tex]
Total area = [tex]\bf{(14+6) \:sq \:m = \:20 \:sq \:m = 2,00,000 \:sq \:cm}[/tex]
[tex]\begin{gathered}\qquad\qquad{(1 \:sq \:m = 10,000 \:sq \:cm).}\end{gathered}[/tex]
Area of 1 tile = [tex]\sf{20cm×20cm=400 \:sq \:cm.}[/tex]
[tex].°.[/tex] number of tiles needed = [tex]\frac{2000 \cancel{00}}{4 \cancel{00}} \:= \: \frac{2000}{4}= \:500.[/tex]
Answer:-
[tex]\begin{gathered}\qquad\qquad\qquad{ - 500}\end{gathered}[/tex]
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Verified answer
[tex]\large{Question:-}[/tex]
The figure shows Me Dhingra's verandah. How many square tiles is side 20cm would he need to tile the floor of the verandah?
Solutions:-
Let us divide the verandah into the rectangle 1 and 2.
Area of rectangle 1 = [tex]\sf{3m×2m=6 \:sq \:m.}[/tex]
Area of rectangle 2 = [tex]\sf{7m×2m=14 \:sq \:m.}[/tex]
Total area = [tex]\bf{(14+6) \:sq \:m = \:20 \:sq \:m = 2,00,000 \:sq \:cm}[/tex]
[tex]\begin{gathered}\qquad\qquad{(1 \:sq \:m = 10,000 \:sq \:cm).}\end{gathered}[/tex]
Area of 1 tile = [tex]\sf{20cm×20cm=400 \:sq \:cm.}[/tex]
[tex].°.[/tex] number of tiles needed = [tex]\frac{2000 \cancel{00}}{4 \cancel{00}} \:= \: \frac{2000}{4}= \:500.[/tex]
Answer:-
[tex]\begin{gathered}\qquad\qquad\qquad{ - 500}\end{gathered}[/tex]