The figure below is comprised of two congruent squares and two congruent triangles. Each side of the squares has a length of x. Each triangle has a height of x.
If x equals 11 cm, what is the total area of the figure?
A.
363 sq cm
B.
605 sq cm
C.
484 sq cm
D.
242 sq cm
If x equals 11 cm, what is the total area of the figure?
A.
363 sq cm
B.
605 sq cm
C.
484 sq cm
D.
242 sq cm
Answers & Comments
Answer:
A. 363 sq cm
Step-by-step explanation:
The total area of the figure is the sum of the areas of the two squares and two triangles. The area of a square with side length x is x ^ 2 , so the combined area of the two squares is 2x ^ 2 . The area of a triangle is half the product of its base and height, so the area of each triangle is 1/2 * xx = 1/2 * x ^ 2 The
combined area of the two triangles is thus 2 * 1/2 * x ^ 2 = x ^ 2 Adding the areas of the squares and triangles, we get the total area of the figure:
= 3 * (11cm) ^ 2
2x ^ 2 + x ^ 2 = 3x ^ 2 = 363c * m ^ 2 .
= 3 * 121c * m ^ 2
Therefore, the answer is (A) 363c * m ^ 2