the donations given to an orphanege home by the students of different classes of a secondary school are given below. (in Rs.)
table :-
CLASS | DONATION BY NO. OF
EACH STUDENTS (in rupees) |
| NO. OF STUDENT DONATED |
VI 5 15
VII 7 15
VIII 10 20
IX 15 16
X 20 14
Find the mean, median and mode of the data.
(I need this answer pls. no Stüpid answers)
table :-
CLASS | DONATION BY NO. OF
EACH STUDENTS (in rupees) |
| NO. OF STUDENT DONATED |
VI 5 15
VII 7 15
VIII 10 20
IX 15 16
X 20 14
Find the mean, median and mode of the data.
(I need this answer pls. no Stüpid answers)
Answers & Comments
Answer:
Donation by each student No. of students donated
Cumulative frequency
5 15 15
7 15 30
10 20 50
15 16 66
20 14 80
To find the mean we will add up total cost of packets , then divide by total number of packets.
So,
Mean =
(15+15+20+16+14)
(5×15+7×15+10×20+15×16+20×14)
Mean =(75+105+200+240+280)/80=900/80=11.26
As we can see that the donation of greatest number of student is Rs. 10 each, so the mode will be 10
As we can see there are 80 students arranged in increasing order of their respective donations. So, the middle one will be (80)/2=40
th
and 41
st
student in the list.
So, the median will be the donation by student corresponding to cumulative frequency just greater or equal to 40 and 41 , i.e., 10
Therefore , median is 10