Answer:

Step-by-step explanation:

Let the point of intersection be P=(p,q).

It can be obtained by solving the equations x+y=11      .........(i)

and x−y=3          .......(ii)

Adding (i) &  (ii) we get,

2x=14⟹x=7

Putting x=7 in equation (i) we get,

y=4  

∴P=(p,q)=(7,4)

The distance d=

p

2

+q

2

​

=

7

2

+4

2

​

=

65

​

 units

Answer:

Ans = 3√5

Step-by-step explanation:

To find the point of intersection,

Add the equations:

x + y = 11

x - y = 3

________

2x = 14 or x = 7 ------- (i)

Substituting the value of x in first equation,

(7) + y = 11

y = 11 - 7 or y = 4 -------- (ii)

So, the point of intersection from (i) and (ii):

( x, y ) = ( 7, 4 )

Now, the coordinates of origin are ( 0, 0 ).

Distance = √{ ( x' - x )² + ( y' - y )² }

= √{ (7-0)² + (4-0)² }

= √{ 49 + 16 }

= √65

Ans = 3√5