Step-by-step explanation:

Let two numbers be x and y and x(larger) y (smaller).

then, x^2-y^2 = 88 ----(2)

A/q ,

x = 2y - 5 ----(1)

Substitute value of x in given eqn 2,

(2y-5) ^2 -y^2 = 88

=>4y^2 + 25 - 20 y - y^2 = 88

=>3y^2 - 20y +25 -88 = 0

=> 3y^2 - 20y - 63 = 0

=>3y^2 - 27y +7y-63 =0

=>3y(y-9) +7(y-9) = 0

( 3y + 7)(y-9) = 0

=> y=9 ( right)

or, y = -7/3 (neglected)

Since Y=9,

Therefore,

x= 2*9 - 5 = 18 - 5 = 13

Hence,the required two numbers are 13 and 9.

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