Let the numbers be x & x+2
According to the question-
(x+2)^2 - x^2=56
(x+2+x)(x+2-x)=56
(2x+2) * 2=56
2x+2=28
2x=26
x=13
x+2=15
the numbers are 13 and 15
Step-by-step explanation:
Let the two consecutive odd number = x and (x + 2 )
To find, the numbers = ?
According to the question,
⇒
∴ x + 2 = 13 + 2 = 15
Hence, the two consecutive odd numbers are 13 and 15.
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Answers & Comments
Let the numbers be x & x+2
According to the question-
(x+2)^2 - x^2=56
(x+2+x)(x+2-x)=56
(2x+2) * 2=56
2x+2=28
2x=26
x=13
x+2=15
the numbers are 13 and 15
The two consecutive odd numbers are "13 and 15".
Step-by-step explanation:
Let the two consecutive odd number = x and (x + 2 )
To find, the numbers = ?
According to the question,
⇒![x^2+4x+4-x^2=56 x^2+4x+4-x^2=56](https://tex.z-dn.net/?f=x%5E2%2B4x%2B4-x%5E2%3D56)
⇒![4x+4=56 4x+4=56](https://tex.z-dn.net/?f=4x%2B4%3D56)
⇒![4x=56-4=52 4x=56-4=52](https://tex.z-dn.net/?f=4x%3D56-4%3D52)
⇒![x=\dfrac{52}{4} =13 x=\dfrac{52}{4} =13](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B52%7D%7B4%7D%20%3D13)
∴ x + 2 = 13 + 2 = 15
Hence, the two consecutive odd numbers are 13 and 15.