Let the numbers be x and y
the number at ones place is y
and number on tens place is 10x
so the digit will be 10x+y
The interchange of digit is =10y+x
It is given the difference between the digit and interchange is 63 so
10x+y−(10y+x)=63
9x−9y=63
x−y=7
The difference between the digits is 7.
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Answers & Comments
Let the numbers be x and y
the number at ones place is y
and number on tens place is 10x
so the digit will be 10x+y
The interchange of digit is =10y+x
It is given the difference between the digit and interchange is 63 so
10x+y−(10y+x)=63
9x−9y=63
x−y=7
The difference between the digits is 7.
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