AyushmaanROXX1
Let the original diameter be x the diameter is decreased by 25% of the original one so the the new diameter = x - 25% of x =3x/4 surface area of a sphere according to its original diameter is equals to 4πr² =4×π×x² = 4x²π surface area of sphere according to its new diameter that is 3 X upon 4 is equals to 4πR² = 4×π×(3x/4)² =27x²π/16 percentage decrease will be new surface area / original surface area × 100 =(27x²π/16)/4x²π×100 = 27/64×100 =42.18%
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Answers & Comments
Hope it helps you
the diameter is decreased by 25% of the original one so the the new diameter = x - 25% of x
=3x/4
surface area of a sphere according to its original diameter is equals to 4πr²
=4×π×x²
= 4x²π
surface area of sphere according to its new diameter that is 3 X upon 4 is equals to 4πR²
= 4×π×(3x/4)²
=27x²π/16
percentage decrease will be new surface area / original surface area × 100
=(27x²π/16)/4x²π×100
= 27/64×100
=42.18%
I hope this will help you and please mark me as brainliest...