The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
(Please add explanation, and maybe a picture if you can...Best answer will be marked as brainliest..)
(Please add explanation, and maybe a picture if you can...Best answer will be marked as brainliest..)
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Verified answer
Answer:
perimeter = 68cm
Step-by-step explanation:
we know that diagonals of rhombus bisect each other perpendicularly
so we get 4 right triangle whose base , altitude are half of the measure of diagonals and hypotenuse as the side of the rhombus
by pythagoras theorem
hypotenuse ²= 8² + 15² =64+225 =289
so hypotenuse = side of rhombus =17cm
we know that 4 sides of rhombus are equal
perimeter = 4× 17 = 68 cm
I hope it will be helpful for you
Answer:
Step-by-step explanation:
Given: Diagonals AC=30cm and DB=16cm.
Since the diagonals of the rhombus bisect at right angle to each other.
Therefore, OD=
2
DB
=
2
16
=8cm
and OC=
2
AC
=
2
30
=15cm
Now, In right angle triangle DOC,
(DC)
2
=(OD)
2
+(CO)
2
⇒(DC)
2
=(8)
2
+(15)
2
⇒(DC)
2
=64+225=289
⇒DC=
289
=17cm
Perimeter of the rhombus=4× side
=4×17=68cm
Thus, the perimeter of rhombus is 68 cm.