Let AB (=24m ) be guy wire attached to a vertical pole BC of height 18 m. To keep the wire taut let it fixed to stake at A Then ABC is a right triangle right angled at C
AB² =AC² +BC²
so ∴24² =AC² +18²
or AC² =576−324
or AC² =252
or AC= √252
AC=6√7m
therefore the stake may be placed at a distance of 6√7 m from the base of pole
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Answer:
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Step-by-step explanation:
Let AB (=24m ) be guy wire attached to a vertical pole BC of height 18 m. To keep the wire taut let it fixed to stake at A Then ABC is a right triangle right angled at C
AB² =AC² +BC²
so ∴24² =AC² +18²
or AC² =576−324
or AC² =252
or AC= √252
AC=6√7m
therefore the stake may be placed at a distance of 6√7 m from the base of pole