The coil of area A is kept parallel in a magneyiv field if coil is rotated by 90 such that its axis is perpendicular to magnetic field the change in flix will be:
When a coil of area A is kept parallel to a magnetic field, the magnetic flux passing through the coil is given by the equation:
Φ = B * A * cosθ
Where:
Φ is the magnetic flux,
B is the magnetic field strength,
A is the area of the coil, and
θ is the angle between the magnetic field and the normal to the coil.
In this case, the coil is rotated by 90 degrees such that its axis becomes perpendicular to the magnetic field. This means that the angle θ becomes 90 degrees.
When θ = 90 degrees, cosθ = 0.
Substituting this into the equation for magnetic flux, we have:
Φ = B * A * cos90°
= B * A * 0
= 0
Therefore, the change in magnetic flux when the coil is rotated by 90 degrees and its axis becomes perpendicular to the magnetic field is zero.
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Answers & Comments
Explanation:
When a coil of area A is kept parallel to a magnetic field, the magnetic flux passing through the coil is given by the equation:
Φ = B * A * cosθ
Where:
Φ is the magnetic flux,
B is the magnetic field strength,
A is the area of the coil, and
θ is the angle between the magnetic field and the normal to the coil.
In this case, the coil is rotated by 90 degrees such that its axis becomes perpendicular to the magnetic field. This means that the angle θ becomes 90 degrees.
When θ = 90 degrees, cosθ = 0.
Substituting this into the equation for magnetic flux, we have:
Φ = B * A * cos90°
= B * A * 0
= 0
Therefore, the change in magnetic flux when the coil is rotated by 90 degrees and its axis becomes perpendicular to the magnetic field is zero.
I have put in so much effort, now it's your turn to give this answer a like and mark it as helpful❤️.