The coach of a cricket team buys 3 bats and 6 balls for Rs.3900. Later, she buys another bat and 3 more balls of the same kind for Rs.1300. Represent this situation algebraically and geometrically.
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Answer:let rate of bat = xRs.
and rate of ball = yRs.
3x+6y=3900.....(i)
and x+3y=1300.....(ii)
or x=(1300−3y
now equation (i) can be written as
3(1300−3y)+6y=3900
3900−9y+6y=3900
∴y=0
Ans:- x=1300
Step-by-step explanation:
Verified answer
Answer:
let rate of bat = xRs.
and rate of ball = yRs.
3x+6y=3900.....(i)
and x+3y=1300.....(ii)
or x=(1300−3y)
now equation (i) can be written as
3(1300−3y)+6y=3900
3900−9y+6y=3900
∴y=0
Ans:- x=1300