[tex]\huge{\bf{\underline{\underline{\green{Given :-}}}}}[/tex]

• The base of an isosceles triangle is 12 cm and its perimeter is 32 cm . Find its area.

[tex]\huge{\bf{\underline{\underline{\green{To Find :-}}}}}[/tex]

• Area of an isosceles triangle

[tex]\huge{\bf{\underline{\underline{\green{Solution :-}}}}}[/tex]

The base of an isosceles triangle is 12 cm and its perimeter is 32 cm . To find out the AREA we need to follow these :-

Let each of the equal side be a cm

Now, a + a = 12 = 32

→ 2a = 32 - 12

→ 2a = 20

→ a = 20/2

→ a = 10

Therefore, b = 12cm

Area of a triangle = { 1/2 × b ×√a² - b²/4 }

[tex]{\bf{\underline{\underline{\green{Unit :-}}}}}[/tex]

• Square Unit

→ { 1/2 × 2 × √100 - 144/4 }

→ ( 6 × √100 - 36 )

→ 6 × 8

→ 48

[tex]\huge{\bf{\underline{\underline{\green{Answer :-}}}}}[/tex]

Hence, the area of an isosceles triangle whose base is 12 cm and its perimeter is 32 cm is 42 cm²

HOPE THIS HELPS YOU