the base of a triangular field is twice its altitude. if the cost of levelling the field,at the rate of Rs 10 per m2 is Rs 4000,find its base and altitude
Answers & Comments
HStar6389
Thecost of level = 10 rs the land be level = 4000/10 =400 m^2 let altitude be = x let base be = 2x The Area of triangle = 1/2*b*H 400=1/2*2x*x 800=2x^2 400=x^2 sq. root 400= x 20 = x
Answers & Comments
the land be level = 4000/10
=400 m^2
let altitude be = x
let base be = 2x
The Area of triangle = 1/2*b*H
400=1/2*2x*x
800=2x^2
400=x^2
sq. root 400= x
20 = x
base = 2x = 2*20= 40m
Altitude= x = 20 m
x is 20, 2x is 40
Rate / m² is ₹10
so, area of the triangle = total rate/ rate per metre
so, 4000/10 = 400 m² is the area
Now,
let altitude be x
base is twice of x which is 2x
area of triangle (formula) = ½b×h
= ½ x×2x = 2x²/2 =400
2x²= 400×2 =800
x²= 800/2 = 400
therefore,
x =
which is 20
so x is 20 and 2x = 40
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