Answer:

The correct answer is C. 19.15%.

Step-by-step explanation:

To calculate the probability of randomly selecting lizards with weights of 13.15 g to 13.6 g, we need to use the standard normal distribution, also known as the Z-distribution. We first need to standardize the values of 13.15 g and 13.6 g to Z-scores using the formula:

Z = (X - μ) / σ

where X is the value we want to standardize, μ is the mean (average) weight of lizards, and σ is the standard deviation of the weights.

For 13.15 g:

Z = (13.15 - 13.2) / 0.8 = -0.0625

For 13.6 g:

Z = (13.6 - 13.2) / 0.8 = 0.5

We can then use a standard normal distribution table or calculator to find the probability of randomly selecting lizards within this range of Z-scores. The probability of selecting lizards with weights between 13.15 g and 13.6 g is:

P(-0.0625 < Z < 0.5) = P(Z < 0.5) - P(Z < -0.0625)

Using a standard normal distribution table, we can find that P(Z < 0.5) = 0.6915 and P(Z < -0.0625) = 0.4726.

Therefore,

P(-0.0625 < Z < 0.5) = 0.6915 - 0.4726 = 0.2189

So the probability of randomly selecting lizards with weights between 13.15 g and 13.6 g is approximately 0.2189 or 21.89%, which is closest to option C. 19.15% is not the correct answer.