Verified answer

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Step-by-step explanation:

• Given the points of triangle, A(p,2−2p),B(1−p,2p) and C(−4−p,6−2p)

Area =70sq.unit

{p[2p−6+2p]+(1−p)[6−2p+2p]+(−4−p)[2−2p−2p]}

=140p(4p−6)+(1−p)(4)−[(4+p)(2−4p)]=1404p²

−6p+4−4p−[8−16p+2p−4p ²

=1404p ²−6p+4−4p−8+16p−2p+4p²

=1408p ²+4p−144

=0²p ²+p−36

=0²p ² +9p−8p−36=0

p(2p+9)−4(2p+9)=0

(2p+9)=0,(p−4)=0

p=−9/2,p=4

Answer:

Given the points of triangle, A(p,2−2p),B(1−p,2p) and C(−4−p,6−2p)

Area =70sq.unit

=21[x1(y2−y3)+x2(y3−y1)x3(y1−y2)]=70{p[2p−6+2p]+(1−p)[6−2p+2p]+(−4−p)[2−2p−2p]}=140p(4p−6)+(1−p)(4)−[(4+p)(2−4p)]=1404p2−6p+4−4p−[8−16p+2p−4p2]=1404p2−6p+4−4p−8+16p−2p+4p2=1408p2+4p−144=02p2+p−36=0

2p2+9p−8p−36=0

p(2p+9)−4(2p+9)=0

(2p+9)=0,(p−4)=0

p=−9/2,p=4