The area of a triangle varies jointly as the base and altitude. The area of a triangle whose altitude is 24cm and whose base 4cm is 48 square cm. Find the altitude of a triangle of equal area whose base is 6cm.
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t=kba
24=k(4)(48)
24=192k
24/192=192k/192
1/8=k
t=(1/8)ba
24=(1/8)(6)a
24=/a
32=a