Verified answer

Question:

The area of a rectangular lot is 45 sq meters. If the length of the lot is 4m more than its width, what is the perimeter of the rectangular lot?

Representation:

• Area - 45
• Width - x
• Length - x + 4

Equation:

• Area of the rectangle = Length x Width
• 45 = (x + 4)(x)

• 45 = (x + 4)(x)
• 0 = x² + 4x - 45
• 0 = (x + 9)(x + 5)
• x = -9, x = -5

• Measurement can't be negative so x is only equal to 9 and 5.

>>>>>>>>>

• Perimeter = 2L + 2W
• 2(9) + 2(5)
• 18 + 10
• 28

• The perimeter of the rectangle is 28 meters.