Answer:

Let x be the width

Let (x + 1) be the length

x(x+1)=30

x^{2}+1x=30 or

x^{2}+x=30

because x is equal to 1 so no need to

add 1

x^{2}+x-30=0

Positive 30 became Negative 30 kase

minove

natin sya

(x-5)(x+6)=0

Find a number na 1 and sagot kapag

i-add man o isubtract basta kapag

minultiply is equal to 30, and we find -5

and 6.

- 5 + 6 = 1 and -5.6 - 30

So that the answer is

The x no. 1 is 5

The x no. 2 is 6

We know that the value of width can't

be negative

Width=5

Length=6