Step-by-step explanation:
Given :
Area of rectangle : 6a²+36a
Breadth : 36a
To Find :
Length
Solution :
We know that,
Area of rectangle = length × breadth
or , length = Area of rectangle/breadth
=> 6a²+36a/36a
=>6a(a + 6)/36
=> (a+6)/6
The required length is (a+6)/6.
Area of rectangle =
=
Breadth =
Length =?
Area = Lenght × Breadth
Length =
∴ The length is equal to .
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Answers & Comments
Step-by-step explanation:
Given :
Area of rectangle : 6a²+36a
Breadth : 36a
To Find :
Length
Solution :
We know that,
Area of rectangle = length × breadth
or , length = Area of rectangle/breadth
=> 6a²+36a/36a
=>6a(a + 6)/36
=> (a+6)/6
The required length is (a+6)/6.
If it helps then mrk me as BRAINLIEST
Area of rectangle =![6a^{2} +36a 6a^{2} +36a](https://tex.z-dn.net/?f=6a%5E%7B2%7D%20%2B36a)
=![6(a^{2} +6a) 6(a^{2} +6a)](https://tex.z-dn.net/?f=6%28a%5E%7B2%7D%20%2B6a%29)
=![6a(a+6) 6a(a+6)](https://tex.z-dn.net/?f=6a%28a%2B6%29)
Breadth =![36a 36a](https://tex.z-dn.net/?f=36a)
Length =?
Area = Lenght × Breadth
Length =![\frac{Area}{Breadth} = \frac{6(a^{2} +6a)}{36a} = \frac{6a(a+b)}{36a} \frac{Area}{Breadth} = \frac{6(a^{2} +6a)}{36a} = \frac{6a(a+b)}{36a}](https://tex.z-dn.net/?f=%5Cfrac%7BArea%7D%7BBreadth%7D%20%3D%20%5Cfrac%7B6%28a%5E%7B2%7D%20%2B6a%29%7D%7B36a%7D%20%3D%20%5Cfrac%7B6a%28a%2Bb%29%7D%7B36a%7D)
Length =![\frac{(a+6)}{a} \frac{(a+6)}{a}](https://tex.z-dn.net/?f=%5Cfrac%7B%28a%2B6%29%7D%7Ba%7D)
∴ The length is equal to
.