The area of a quarantine facility is 117m². If the length x is 4 meters more than its width, what is the correct equation that illustrates the problem?
A.) x (40x) = 117
B.) x (x+4) = 117
C.) x + x+4 = 117
D.) x(4x) = 117
A.) x (40x) = 117
B.) x (x+4) = 117
C.) x + x+4 = 117
D.) x(4x) = 117
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Answer:
C. x + x + 4 = 117
x = 4 meters more than x