the area of a classroom is 54 sq. m, and the width is 3 meters less than the length. what is the perimeter of the classroom? solve by factoring
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Answer:
P = 30m
Step-by-step explanation:
A = lw
P = 2(l+w)
A = 54 sq m
w = l - 3
Substitute
A = lw
54 = l(l-3)
54 = l^2 - 3l
Transpose
l^2 - 3l - 54 =0
(l -9)(l + 6) = 0
l - 9 = 0
l = 9m
l + 6= 0
l = -6
Note: Take only the positive value as we are dealing with dimensions
l = 9m
w = l -3
w = 9 - 3
w = 6m
P = 2(l+w)
P = 2(9+6)
P = 2(15)
P = 30m