Step-by-step explanation:
Area (ΔHEF) = 1/2Area (ABFH) … (1)
Similarly, it can be proved that
On adding equations (1) and (2), we get
area of ΔEFH + area of ΔGHF = ½ ar
⇒ area of EFGH = area of ABFH
[tex]\huge {\green {\sf {\underline {\underline {Answer}}}:-}}[/tex]
Given, The angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13.
To find, All the angles of the quadrilateral.
The sum of interior angles in a quadrilateral is 360 degrees.
Let the angles of the quadrilateral be 3x, 5x, 9x, and 13x respectively.
The sum of all interior angles of a quadrilateral is 360°.
[tex]3x + 5x + 9x + 13x = 360° \\ →30x = 360° \\ x = 12° \\ Hence, \: the \: angles \: are
\\ 3x = 3 × 12 = 36° \\ 5x = 5 × 12 = 60° \\ 9x = 9 × 12 = 108° \\ 13x = 13 × 12 = 156°[/tex]
[tex]\huge\dag\sf\red{By \: Divyanshu}[/tex]
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Verified answer
Step-by-step explanation:
Area (ΔHEF) = 1/2Area (ABFH) … (1)
Similarly, it can be proved that
On adding equations (1) and (2), we get
area of ΔEFH + area of ΔGHF = ½ ar
⇒ area of EFGH = area of ABFH
[tex]\huge {\green {\sf {\underline {\underline {Answer}}}:-}}[/tex]
Given, The angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13.
To find, All the angles of the quadrilateral.
The sum of interior angles in a quadrilateral is 360 degrees.
Let the angles of the quadrilateral be 3x, 5x, 9x, and 13x respectively.
The sum of all interior angles of a quadrilateral is 360°.
[tex]3x + 5x + 9x + 13x = 360° \\ →30x = 360° \\ x = 12° \\ Hence, \: the \: angles \: are
\\ 3x = 3 × 12 = 36° \\ 5x = 5 × 12 = 60° \\ 9x = 9 × 12 = 108° \\ 13x = 13 × 12 = 156°[/tex]
[tex]\huge\dag\sf\red{By \: Divyanshu}[/tex]