The angle of elevation of the top of the tower when observed from a point distance 90m from the foot of the tower is 60° then find the height of the tower ?
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Let the height of the tower =hm
and the distance between building and tower =xm
Now, in △AED,
⇒tanx=
a
60
⇒atanx=60⟶(1)
Again, △BAC,
⇒tanx=
a
(h−60)
⇒atanx=h−60⟶(2)
From equations (1)ξ(2), we get
⇒h−60=60
⇒h=120
∴ Height of tower 120m
Hence, the answer is 120.