The angle of elevation of the top of a tower from a point at a distance of 100m from the base of the tower is found to be 45°. The height of the tower is
The angle of elevation of the top of a tower from a point at a distance of 100m from the base of the tower is found to be 45°. The height of the tower is 100m
Answers & Comments
Answer :
Height of tower = 100 m
Solution :
Given,
Angle of elevation = 45°
Distance from foot of tower to the observer = 100 m
tan θ = opp/adj
tan 45° = h/100
1 = h/100
h = 100
Therefore,
Height of the tower = 100 m
The angle of elevation of the top of a tower from a point at a distance of 100m from the base of the tower is found to be 45°. The height of the tower is 100m