The ages of three siblings are consecutive such that the product of the two younger is two (2) more than (10) times the eldest. What are their ages?
Find out if this problem is solvable if not why?
Find out if this problem is solvable if not why?
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Answer:
12 years
Step-by-step explanation:
Let x = the age of the youngest child
Let x + 1 = the age of the middle child
Let x + 2 = the age of the oldest child
x + x + 1 + x + 2 = 39
3x + 3 = 39
3x = 36
x = 12 years
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