Answer:
Step-by-step explanation:
Let The present age of B be X years.
Then the age of A = ( X + 5) years.
Before Five years age of A = ( X +5 - 5) = X years.
Before Five years age of B = ( X -5) years.
According to question ,
A : B = 3:2
X / X -5 = 3/2
2 ( X )= 3 ( X -5)
2X = 3X -15
3X - 2X = 15
X = 15 years.
Present age of B = X = 15 years
And,
Present age of A = X +5 = 15+5 = 20 years.
Let the age of B is x
And A is (x+5)
Five years ago, B=x-5
ㅤㅤㅤㅤㅤㅤㅤA=x+5-5=x
⇢[tex] \sf \dfrac{A}{B}[/tex]=[tex] \sf \dfrac{3}{2}[/tex]=[tex] \sf \dfrac{x}{x-5}[/tex]
⇢(x-5)3=x(2)
⇢3x-15=2x
⇢x=15
Hence present age of A is [tex] \sf \pink{15 \ years}[/tex]
Present age of B is x+5
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ=15+5
ㅤㅤㅤㅤㅤㅤㅤ⇢[tex] \sf \pink{20 \ years}[/tex]
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Verified answer
Answer:
Step-by-step explanation:
Let The present age of B be X years.
Then the age of A = ( X + 5) years.
Before Five years age of A = ( X +5 - 5) = X years.
Before Five years age of B = ( X -5) years.
According to question ,
A : B = 3:2
X / X -5 = 3/2
2 ( X )= 3 ( X -5)
2X = 3X -15
3X - 2X = 15
X = 15 years.
Present age of B = X = 15 years
And,
Present age of A = X +5 = 15+5 = 20 years.
Solution:
Let the age of B is x
And A is (x+5)
Five years ago, B=x-5
ㅤㅤㅤㅤㅤㅤㅤA=x+5-5=x
⇢[tex] \sf \dfrac{A}{B}[/tex]=[tex] \sf \dfrac{3}{2}[/tex]=[tex] \sf \dfrac{x}{x-5}[/tex]
⇢(x-5)3=x(2)
⇢3x-15=2x
⇢x=15
Hence present age of A is [tex] \sf \pink{15 \ years}[/tex]
Present age of B is x+5
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ=15+5
ㅤㅤㅤㅤㅤㅤㅤ⇢[tex] \sf \pink{20 \ years}[/tex]