Answer:
Here lets take angle abc as z....y=100 (alt in angles)z+100 = 180 (linear pair )
z= 180 -100
z=80angle A + B + C + z = 360 (Quadrilateral )
x+100+80+80 = 360
x=360-260
x=100
x=100y=100
y=100 and x=80
Step-by-step explanation:
ABC and BCE are alternate angle and BC is a transversal
so angle B = angle C
so y=100
now AB forms a Linear pair so sum of angles is 180 degree
so if y=100 and x=? then x+y=180
then 100+x=180
x=80
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Answer:
Here lets take angle abc as z....
y=100 (alt in angles)
z+100 = 180 (linear pair )
z= 180 -100
z=80
angle A + B + C + z = 360 (Quadrilateral )
x+100+80+80 = 360
x=360-260
x=100
x=100
y=100
Answer:
y=100 and x=80
Step-by-step explanation:
ABC and BCE are alternate angle and BC is a transversal
so angle B = angle C
so y=100
now AB forms a Linear pair so sum of angles is 180 degree
so if y=100 and x=? then x+y=180
then 100+x=180
x=80