the 8th term of an ap is half of its second term and 11th term exceeds one third of its fourth term by 1. find the 15th term...please answer the question ❓❓❓❓don't spam pleasedrop some thanks please. Created by Sadhana4748. Math

the 8th term of an ap is half of its second term and 11th term exceeds one third...

Answer:

Step-by-step explanation:

Given, an A.P in which,

a8 = 1/2(a2) a11 = 1/3(a4) + 1

We know that an = a + (n – 1)d

⇒ a8 = 1/2(a2) a + 7d = 1/2(a + d) 2a + 14d = a + d a + 13d = 0 …… (i)

And, a11 = 1/3(a4) + 1 a + 10d = 1/3(a + 3d) + 1 3a + 30d = a + 3d + 3 2a + 27d = 3 …… (ii)

Solving (i) and (ii), by (ii) – 2x(i)

⇒ 2a + 27d – 2(a + 13d) = 3 – 0 d = 3

Putting d in (i) we get, a + 13(3) = 0 a = -39

Thus, the 15th term a15 = -39 + 14(3) = -39 + 42 = 3

✧═════════════•❁❀❁•══════════════✧ $\huge\color{Pink}\boxed{\colorbox{Black}{❥Mysteryboy01}}$

✧═════════════•❁❀❁•══════════════✧

$\huge\color{white}\boxed{\colorbox{black}{♡︎Your Introduction♡︎}}$

$\huge\star\underline{\mathtt\orange{❥Good} \mathfrak\blue{Mo}\mathfrak\blue{r} \mathbb\purple{ ni}\mathtt\orange{n} \mathbb\pink{g}}\star\:$

$\huge\star\huge{ \pink{\bold {\underline {\underline {\red {Great Day }}}}}} \star$

$\huge\blue\bigstar\pink{Be Safe Always }$

$\huge\fbox \red{✔Que} {\colorbox{crimson}{est}}\fbox\red{ion✔}$

$\huge\color{Red}\boxed{\colorbox{black}{♡Answer ♡}}$

$\huge\mathscr\red{♡❤Cute boy❤♡}$

$\huge \mathbb{ \red {★᭄ꦿ᭄Mark} \pink{a}\purple{s} \blue {Brain} \orange{lis} \green{t★᭄ꦿ᭄}}$