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juveria11
@juveria11
July 2022
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The 4th term of a geometric progression is 2÷3 and the 7th term is 16÷81.Find the geometric series.
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anjalijugral
Verified answer
Answer see in image
The g. P. Is 9/4,3/2,1,2/3----
18 votes
Thanks 28
anjalijugral
thanku
juveria11
welcome
juveria11
you done this answer for me
juveria11
so thanks
anjalijugral
its my pleasure
HappiestWriter012
Verified answer
We know that nth term of a geometric progression is a*r^n-1 .
Now fourth term = ar³ =2/3
Seventh term = ar^6 = 16/81
Dividing the above, we get
r³ = 16/81 ÷ 2/3
r³ = 16/81 * 3/2
r³ = 8/27
r = 2/3 .
Now, ar³ = 2/3
a = 2/3 ÷ 8/27
a = 2/3 * 27/8 = 9/4 .
ar = 9/4(2/3) = 3/2
ar² = 9/4(4/9) = 1
ar³ = 2/3
Therefore, the geometric progression is as follows :- 9/4 , 3/2 , 1 ,2/3 ...
10 votes
Thanks 21
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Answers & Comments
Verified answer
Answer see in imageThe g. P. Is 9/4,3/2,1,2/3----
Verified answer
We know that nth term of a geometric progression is a*r^n-1 .Now fourth term = ar³ =2/3
Seventh term = ar^6 = 16/81
Dividing the above, we get
r³ = 16/81 ÷ 2/3
r³ = 16/81 * 3/2
r³ = 8/27
r = 2/3 .
Now, ar³ = 2/3
a = 2/3 ÷ 8/27
a = 2/3 * 27/8 = 9/4 .
ar = 9/4(2/3) = 3/2
ar² = 9/4(4/9) = 1
ar³ = 2/3
Therefore, the geometric progression is as follows :- 9/4 , 3/2 , 1 ,2/3 ...