Question
y=2x
2
−4+4
Rewrite the equation
Rewrite in polar form
r=0
r=
1+cos(2θ)
sin(θ)
Evaluate
Add the terms
Move the expression to the left side
y−2x
=0
To convert the equation to polar coordinates,substitute x for r×cos(θ) and y for r×sin(θ)
sin(θ)r−2(cos(θ)r)
Factor the expression
−2cos
(θ)r
+sin(θ)r=0
Simplify the expression
(−1−cos(2θ))r
r((−1−cos(2θ))r+sin(θ))=0
When the product of factors equals 0,at least one factor is 0
(−1−cos(2θ))r+sin(θ)=0
Solution
Function
Find the vertex
(0,0)
Testing for symmetry
Testing for symmetry about the origin
Not symmetry with respect to the origin
Identify the conic
Write the equation in standard form
x
=
1
y
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Answers & Comments
Answer and explation
Question
y=2x
2
−4+4
Rewrite the equation
Rewrite in polar form
r=0
r=
1+cos(2θ)
sin(θ)
Evaluate
y=2x
2
−4+4
Add the terms
y=2x
2
Move the expression to the left side
y−2x
2
=0
To convert the equation to polar coordinates,substitute x for r×cos(θ) and y for r×sin(θ)
sin(θ)r−2(cos(θ)r)
2
=0
Factor the expression
−2cos
2
(θ)r
2
+sin(θ)r=0
Simplify the expression
(−1−cos(2θ))r
2
+sin(θ)r=0
Factor the expression
r((−1−cos(2θ))r+sin(θ))=0
When the product of factors equals 0,at least one factor is 0
r=0
(−1−cos(2θ))r+sin(θ)=0
Solution
r=0
r=
1+cos(2θ)
sin(θ)
Function
Find the vertex
(0,0)
Testing for symmetry
Testing for symmetry about the origin
Not symmetry with respect to the origin
Identify the conic
Write the equation in standard form
x
2
=
2
1
y