Find value of
x & y
[tex]21x + 6y = 57 \: \\ [/tex]
[tex]24x + \frac{7}{2}y = \frac{103}{2} [/tex]
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x & y
[tex]21x + 6y = 57 \: \\ [/tex]
[tex]24x + \frac{7}{2}y = \frac{103}{2} [/tex]
You have courage to solve this problem...
& Anyone solves the answ first, I will make it brainliest
Answers & Comments
Step-by-step explanation:
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Answer:
21x + 6y = 57
24x + 7/2 y = 103/2
MULTIPLYING BOTH THE EQUATIONS WITH 2
42x + 12y = 114 ------ (1) × 7
48x + 7y = 103 -------(2) × 12
By elimination process,
294x + 84y = 798
576x + 84y = 1236
- - -
_______________
-282x = -438
x = - 438/ - 282
x = 73/47 = 1.5(approx)
putting the value of x in 1 we get
y = 4.1(approx)