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[tex]a \: teacher \: wrote \: the \: expression \: ( \: 4 \: + \: 2 \: \times \: 5 \: ) \: \div \: 7 \: + \: {2}^{3} on \: the \: board \: and \: called \: two \: pupils \: to \: solve \: it.[/tex]
Below are the solutions of two pupils.

Pupil 1
[tex](4 \: + \: 2 \: \times \: 5) \: 7 \: + \: {2}^{3} \: (4 \: + \: 2 \: \times \: 5 \: ) \: \div \: 7 \: + \: {2}^{3} \\ = (6 \: \times \: 5) \: \div \: 7 \: + \: {2}^{3} \\ = 30 \: \div \: 7 \: + {2}^{3} \\ = 30 \: \div \: 7 \: + \: 8 \\ = 30 \: \div \: 15 \\ = 2[/tex]
Pupil 2
[tex] = (4 + 10) \div 7 + {2}^{3} \\ = 14 \: \div \: 7 \: + \: 8 \\ = 2 + 8 \\ = 10 [/tex]
Whose solution do you think is correct? Why? _______________

(Correct Answers Only Nor Memes)​